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Q: Is the square root of 25 an integer?

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Well, the square root of 25 is five, and 5 is an integer, yes.

The opposite of the integer of -25

The symbol is not considered an integer. Thevalue of the square root is, though.

The square root of 25 is 5, which is a whole number, an integer, a natural number and a rational number.

The square root of an integer is a CYCLOTOMIC integer.

√479 ≈ 21.89 √500 ≈ 22.36 Making 22 as the integer between them.

No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.

42 is 16, less than 20 52 is 25, more than 20. so, 20 is not a perfect square, and does not have an integral square root. But, the square root of any integer is either an integer itself, or irrational. So, square root 20 is irrational

Yes, e.g. sqrt(25)=5

no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...

Negative 64 is the square root of an integer. The square root of -64 is not an integer.

A number such as 4, 25, 16, whose square root is an integer.

The square root of 3 is not an integer.

Is the square root of a 100 is a integer

-- If the square root is an integer, then add ' 1 ' to it. -- If the square root is not an integer, then there isn't any.

The square root of 36 is 6 which is an integer.

Yes it is.Since the square of an integer is called a perfect square, then the square root of a perfect square must be an integer.

The square root of 4 is 2 (and -2) and is an integer.

No, the square root of 24 is NOT an integer. An integer is a whole number, and the square root of 24 is 4.89897948557.

Yes. The square root of a positive integer can only be an integer (if your integer is a perfect square), or an irrational number (if it isn't).

Irrational. The square root of a positive integer is either an integer (that is, if the integer is a perfect square), or an irrational number.

Yes and no. It depends on your definition of square root. By the actual one, yes. All non-negative numbers have a square root. That square root might be irrational but it has a square root, nonetheless. 10 isn't a square number because there's no integer that can be squared to make ten but 10 definitely has a square root: 3.16227766....... If by square root you mean an integer square root, then no. If a number has an integer as its square root then you could square that integer to get the number, making it a square number.

The square root of 48 is not an integer which means a whole number.

The square root of 2 is irrational. In general, the square root of a positive integer is either an integer (if you take the square root of a perfect square), or it is irrational.

Yes; the square root of 225 is both a positive and a negative 15. Therefore, the square root of 225 is an integer.