|AMGPGCRYPT(8)||System Administration Commands||AMGPGCRYPT(8)|
NAME¶amgpgcrypt - reference crypt program for Amanda public-key data encryption
amgpgcrypt to be called by Amanda only
DESCRIPTION¶amgpgcrypt calls gpg to perform public-key data encryption on Amanda backup. amgpgcrypt will search for the gpg program in the following directories: /usr/local/bin:/usr/bin:/usr/sbin:/bin:/sbin
amgpgcrypt sets GNUPGHOME to $AMANDA_HOME/.gnupg where gpg will look for the gpg keys. amgpgcrypt uses the public key to encrypt the Amanda data and uses the private key to decrypt the Amanda backup data. Thus, passphrase is only required at the time of data restore.
KEY AND PASSPHRASE¶amgpgcrypt uses the private key to decrypt Amanda backup data.
It is very important to store, manage and protect the key and the passphrase properly. Encrypted backup data can only be recovered with the correct key and passphrase.
HOW TO CREATE ENCRYPTION KEYS AND PASSPHRASE FOR AMGPGCRYPT¶Store the passphrase that you used in following "gpg --gen-key" command inside the home-directory of the AMANDA-user($amanda_user) and protect it with proper permissions:
echo my_secret_passphrase > ~$amanda_user/.am_passphrase chown $amanda_user:disk ~$amanda_user/.am_passphrase chmod 700 ~$amanda_user/.am_passphrase
Run "gpg --gen-key". Below is an example:
$ gpg --gen-key gpg (GnuPG) 1.2.6; Copyright (C) 2004 Free Software Foundation, Inc. This program comes with ABSOLUTELY NO WARRANTY. This is free software, and you are welcome to redistribute it under certain conditions. See the file COPYING for details. Please select what kind of key you want: (1) DSA and ElGamal (default) (2) DSA (sign only) (4) RSA (sign only) Your selection? 1 DSA keypair will have 1024 bits. About to generate a new ELG-E keypair. minimum keysize is 768 bits default keysize is 1024 bits highest suggested keysize is 2048 bits What keysize do you want? (1024) Requested keysize is 1024 bits Please specify how long the key should be valid. 0 = key does not expire (n) = key expires in n days (n)w = key expires in n weeks (n)m = key expires in n months (n)y = key expires in n years Key is valid for? (0) 6m Key expires at Sun 06 Aug 2006 03:51:25 PM PDT Is this correct (y/n)? y You need a User-ID to identify your key; the software constructs the user id from Real Name, Comment and Email Address in this form: "Heinrich Heine (Der Dichter) (firstname.lastname@example.org)" Real name: backup Email address: Comment: gpg keys for backup You selected this USER-ID: "backup (gpg keys for backup)" Change (N)ame, (C)omment, (E)mail or (O)kay/(Q)uit? o You need a Passphrase to protect your secret key. We need to generate a lot of random bytes. It is a good idea to perform some other action (type on the keyboard, move the mouse, utilize the disks) during the prime generation; this gives the random number generator a better chance to gain enough entropy. We need to generate a lot of random bytes. It is a good idea to perform some other action (type on the keyboard, move the mouse, utilize the disks) during the prime generation; this gives the random number generator a better chance to gain enough entropy. public and secret key created and signed. key marked as ultimately trusted. pub 1024D/4417A8CB 2006-02-07 backup (gpg keys for backup) Key fingerprint = 139C 6369 44FC 7F1A 655C E5E9 7EAA 515A 4417 A8CB sub 1024g/8C3A6A78 2006-02-07 [expires: 2006-08-06]
BUGS¶Amanda has problem with gpg mdc(modification detection code) in the binary mode. amgpgcrypt calls gpg with mdc disabled
SEE ALSO¶amanda(8), amanda.conf(5), amcrypt(8), amrestore(8), gpg(1)
The Amanda Wiki: : http://wiki.zmanda.com/
AUTHOR¶Kevin Till <email@example.com>