CTRSYL solves the complex Sylvester matrix equation:

    op(A)*X + X*op(B) = scale*C or
    op(A)*X - X*op(B) = scale*C,

 where op(A) = A or A**H, and A and B are both upper triangular. A is
 M-by-M and B is N-by-N; the right hand side C and the solution X are
 M-by-N; and scale is an output scale factor, set <= 1 to avoid
 overflow in X.

          TRANA is CHARACTER*1
          Specifies the option op(A):
          = 'N': op(A) = A    (No transpose)
          = 'C': op(A) = A**H (Conjugate transpose)

          TRANB is CHARACTER*1
          Specifies the option op(B):
          = 'N': op(B) = B    (No transpose)
          = 'C': op(B) = B**H (Conjugate transpose)

          ISGN is INTEGER
          Specifies the sign in the equation:
          = +1: solve op(A)*X + X*op(B) = scale*C
          = -1: solve op(A)*X - X*op(B) = scale*C

          M is INTEGER
          The order of the matrix A, and the number of rows in the
          matrices X and C. M >= 0.

          N is INTEGER
          The order of the matrix B, and the number of columns in the
          matrices X and C. N >= 0.

          A is COMPLEX array, dimension (LDA,M)
          The upper triangular matrix A.

          LDA is INTEGER
          The leading dimension of the array A. LDA >= max(1,M).

          B is COMPLEX array, dimension (LDB,N)
          The upper triangular matrix B.

          LDB is INTEGER
          The leading dimension of the array B. LDB >= max(1,N).

          C is COMPLEX array, dimension (LDC,N)
          On entry, the M-by-N right hand side matrix C.
          On exit, C is overwritten by the solution matrix X.

          LDC is INTEGER
          The leading dimension of the array C. LDC >= max(1,M)

          SCALE is REAL
          The scale factor, scale, set <= 1 to avoid overflow in X.

          INFO is INTEGER
          = 0: successful exit
          < 0: if INFO = -i, the i-th argument had an illegal value
          = 1: A and B have common or very close eigenvalues; perturbed
               values were used to solve the equation (but the matrices
               A and B are unchanged).