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Q: Find two consecutive even whole numbers whose product is 120?

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1 and 2, whose product is 2.

They are: 32*33 = 1056

Consecutive numbers are whole numbers whose difference is 1.

There is no set of four consecutive whole numbers whose sum is 75.

For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.

There is no set of 8 consecutive whole numbers whose sum is 75.

There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.

The numbers are 64 and 65.

The product between the consecutive prime numbers of 31 and 29 yield a result of 899.

There is no set of 3 consecutive odd numbers whose product is 6,873. However, there is a set of 3 consecutive odd numbers whose sum is 6,873: 2289, 2291, and 2293.

24,25,26

The numbers are 18 and 20.

The product of the prime numbers 19 and 23 is 437.

The numbers are 3, 4 and 5.

The numbers are 9, 11 and 13.

5 AND 7

That isn't possible.

If you mean consecutive numbers then they are 23*24 = 552

The numbers are 746, 747 and 748, as well as 745, 747 and 749 using only consecutive odd whole numbers.

You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.

1, 2, 3

1722 = 41 x 42

899 is 29 x 31

They are 16 and 18

They are: 24*25*26 = 15600